3.2718 \(\int \frac {(b x^n)^p}{x^3} \, dx\)

Optimal. Leaf size=20 \[ -\frac {\left (b x^n\right )^p}{x^2 (2-n p)} \]

[Out]

-(b*x^n)^p/(-n*p+2)/x^2

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Rubi [A]  time = 0.01, antiderivative size = 20, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {15, 30} \[ -\frac {\left (b x^n\right )^p}{x^2 (2-n p)} \]

Antiderivative was successfully verified.

[In]

Int[(b*x^n)^p/x^3,x]

[Out]

-((b*x^n)^p/((2 - n*p)*x^2))

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[(a^IntPart[m]*(a*x^n)^FracPart[m])/x^(n*FracPart[m]), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rubi steps

\begin {align*} \int \frac {\left (b x^n\right )^p}{x^3} \, dx &=\left (x^{-n p} \left (b x^n\right )^p\right ) \int x^{-3+n p} \, dx\\ &=-\frac {\left (b x^n\right )^p}{(2-n p) x^2}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 18, normalized size = 0.90 \[ \frac {\left (b x^n\right )^p}{x^2 (n p-2)} \]

Antiderivative was successfully verified.

[In]

Integrate[(b*x^n)^p/x^3,x]

[Out]

(b*x^n)^p/((-2 + n*p)*x^2)

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fricas [A]  time = 0.67, size = 22, normalized size = 1.10 \[ \frac {e^{\left (n p \log \relax (x) + p \log \relax (b)\right )}}{{\left (n p - 2\right )} x^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^n)^p/x^3,x, algorithm="fricas")

[Out]

e^(n*p*log(x) + p*log(b))/((n*p - 2)*x^2)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (b x^{n}\right )^{p}}{x^{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^n)^p/x^3,x, algorithm="giac")

[Out]

integrate((b*x^n)^p/x^3, x)

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maple [A]  time = 0.00, size = 19, normalized size = 0.95 \[ \frac {\left (b \,x^{n}\right )^{p}}{\left (n p -2\right ) x^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^n)^p/x^3,x)

[Out]

1/x^2/(n*p-2)*(b*x^n)^p

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maxima [A]  time = 0.60, size = 19, normalized size = 0.95 \[ \frac {b^{p} {\left (x^{n}\right )}^{p}}{{\left (n p - 2\right )} x^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^n)^p/x^3,x, algorithm="maxima")

[Out]

b^p*(x^n)^p/((n*p - 2)*x^2)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.05 \[ \int \frac {{\left (b\,x^n\right )}^p}{x^3} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^n)^p/x^3,x)

[Out]

int((b*x^n)^p/x^3, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \begin {cases} \frac {b^{p} \left (x^{n}\right )^{p}}{n p x^{2} - 2 x^{2}} & \text {for}\: n \neq \frac {2}{p} \\\int \frac {\left (b x^{\frac {2}{p}}\right )^{p}}{x^{3}}\, dx & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**n)**p/x**3,x)

[Out]

Piecewise((b**p*(x**n)**p/(n*p*x**2 - 2*x**2), Ne(n, 2/p)), (Integral((b*x**(2/p))**p/x**3, x), True))

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